document.write( "Question 171594: what would log3 28 be and use log6 3= 0.1613147 and log6 5=0.898244 to find log6 45. \n" ); document.write( "
Algebra.Com's Answer #126741 by nerdybill(7384)\"\" \"About 
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what would log3 28 be\r
\n" ); document.write( "\n" ); document.write( "log3 28 = log(28)/log(3) = 1.4472/0.4771 = 0.6905\r
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\n" ); document.write( " use log6 3= 0.1613147 and log6 5=0.898244 to find log6 45.\r
\n" ); document.write( "\n" ); document.write( "since we can rewrite
\n" ); document.write( "log6 45 = log6(5*3*3)
\n" ); document.write( "log6 45 = log6(5) + log6(3) + log6(3)
\n" ); document.write( "log6 45 = 0.898244 + 0.1613147 + 0.1613147 = 1.2208734\r
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