document.write( "Question 171594: what would log3 28 be and use log6 3= 0.1613147 and log6 5=0.898244 to find log6 45. \n" ); document.write( "
Algebra.Com's Answer #126741 by nerdybill(7384) You can put this solution on YOUR website! what would log3 28 be\r \n" ); document.write( "\n" ); document.write( "log3 28 = log(28)/log(3) = 1.4472/0.4771 = 0.6905\r \n" ); document.write( "\n" ); document.write( "********************************************** \n" ); document.write( " use log6 3= 0.1613147 and log6 5=0.898244 to find log6 45.\r \n" ); document.write( "\n" ); document.write( "since we can rewrite \n" ); document.write( "log6 45 = log6(5*3*3) \n" ); document.write( "log6 45 = log6(5) + log6(3) + log6(3) \n" ); document.write( "log6 45 = 0.898244 + 0.1613147 + 0.1613147 = 1.2208734\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |