document.write( "Question 171594: what would log3 28 be and use log6 3= 0.1613147 and log6 5=0.898244 to find log6 45. \n" ); document.write( "

Algebra.Com's Answer #126740 by Alan3354(69443) $\"\"$ $\"About$

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what would log3 28 be
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\n" ); document.write( " $\"log%283%2C28%29+=+ln%2828%29%2Fln%283%29\"$ (or log base 10, just so they match)
\n" ); document.write( " $\"log%283%2C28%29\"$ =~ 3.0331
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\n" ); document.write( "and use log6 3= 0.1613147 and log6 5=0.898244 to find log6 45.
\n" ); document.write( "45 = 3*3*5
\n" ); document.write( " $\"log%286%2C45%29+=+2%2Alog%286%2C3%29%2Blog%286%2C5%29\"$
\n" ); document.write( " $\"log%286%2C45%29+=+2%2A0.1613147+%2B+0.898244\"$
\n" ); document.write( " $\"log%286%2C45%29+=+1.2208734\"$ or it would if $\"log%286%2C3%29+=+0.1613147\"$
\n" ); document.write( "It doesn't.
\n" ); document.write( " $\"log%286%2C3%29+=+0.613147\"$
\n" ); document.write( "That makes the $\"log%286%2C45%29+=+2.1245388\"$ \r
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