document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=23989>Question 23989</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve this 2f(5)=_________    if fx=3x+4????? thank you  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #12673 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=12673\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If f(x) = 3x + 4  then f(5) means to substitute 5 in place of all the x's that might be in the problem.\r<BR>\n" );
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document.write( "f(x) = 3x+4<BR>\n" );
document.write( "f(5) = 3*5+ 4<BR>\n" );
document.write( "f(5)= 15+4<BR>\n" );
document.write( "f(5) =19\r<BR>\n" );
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document.write( "2f(5)<BR>\n" );
document.write( "2*19<BR>\n" );
document.write( "38\r<BR>\n" );
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document.write( "R^2 at SCC<BR>\n" );
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