document.write( "Question 171558: log12^x=1
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document.write( "solve for x \n" );
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Algebra.Com's Answer #126712 by stanbon(75887) ![]() You can put this solution on YOUR website! log12^x=1\r \n" ); document.write( "\n" ); document.write( "xlog(12) = 1 \n" ); document.write( "x = 1/log(12) \r \n" ); document.write( "\n" ); document.write( "x = 1/1.07918...\r \n" ); document.write( "\n" ); document.write( "x = 0.9266... \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |