document.write( "Question 171558: log12^x=1
\n" ); document.write( "solve for x
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Algebra.Com's Answer #126712 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
log12^x=1\r
\n" ); document.write( "\n" ); document.write( "xlog(12) = 1
\n" ); document.write( "x = 1/log(12) \r
\n" ); document.write( "\n" ); document.write( "x = 1/1.07918...\r
\n" ); document.write( "\n" ); document.write( "x = 0.9266...
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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