document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=171496>Question 171496</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Basal energy requirement.  The basal energy requirement B is the number of calories that a person needs to maintain the life process.  For a 28 yaer-old female with a height of 160 centimeters and a weight of 45 kilograms(kg), B is 1300 calories.  If her weight increases to 50kg, then B is 1365 calories.  There is a linear equation that expresses B in therms of her weight w. Find the equation and find the basal energy requirement if her weight is 53.2 kg.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #126634 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=126634\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The basal energy requirement B is the number of calories that a person needs to maintain the life process.<BR>\n" );
document.write( "For a 28 year-old female with a height of 160 centimeters and a weight of 45 kilograms(kg), B is 1300 calories. Point (45,1300)<BR>\n" );
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document.write( "If her weight increases to 50kg, then B is 1365 calories. There is a linear equation that expresses B in terms of her weight w. Point (50,1365)<BR>\n" );
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document.write( "Find the equation and find the basal energy requirement if her weight is 53.2 kg. <BR>\n" );
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document.write( "slope = (1365-1300)/(50-45) = 65/5 = 13<BR>\n" );
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document.write( "intercept: 1300 = 13*45 + b<BR>\n" );
document.write( "b = 715<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "B = 13wt. + 715<BR>\n" );
document.write( "If wt = 53.2, solve for B<BR>\n" );
document.write( "B(53.2) = 13*53.2 + 715<BR>\n" );
document.write( "B(53.2) = 1406.6<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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