document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=171475>Question 171475</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How would f(x)=x+3 look like graphed?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #126625 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=126625\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How would f(x)=x+3 look like graphed?<BR>\n" );
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document.write( "Since it's linear, no exponents >1, it will be a straight line.<BR>\n" );
document.write( "In slope-intercept form (y = mx + b), the slope m is 1, and the y-intercept is 3.  A slope of 1 is (on the most common graph paper) 45 degs, increasing left to right.<BR>\n" );
document.write( "So, it's a line, 45 degs, going thru the point (0,3).<BR>\n" );
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