document.write( "Question 171418: I need help with solving and graphing one cycle of y= 2sin(3x-pi) and y = -3 cos(1/2x)-4.\r
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document.write( "So far for the first question I have gotten really mixed up but I got
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document.write( "3x-pi =o
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document.write( "x=pi/3
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document.write( "x=pi/2
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Algebra.Com's Answer #126614 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! I need help with solving and graphing one cycle of y= 2sin(3x-pi) and y = -3 cos(1/2x)-4. \n" ); document.write( "---------------- \n" ); document.write( "y= 2sin(3x-pi) \n" ); document.write( "Period = (2/3)pi \n" ); document.write( "That tells you the distance from peak to peak. \n" ); document.write( "------------------- \n" ); document.write( "Amplitude = 2 \n" ); document.write( "That tells you the height of each peak \n" ); document.write( "------------------- \n" ); document.write( "x-intercept \n" ); document.write( "2sin(3x-pi) = 0 \n" ); document.write( "sin(3x-pi) = 0 \n" ); document.write( "3x-pi = 0 \n" ); document.write( "x = pi/3 \n" ); document.write( "Mark that point on the x-axis. \n" ); document.write( "It is the point where the curve crosses the x-axis \n" ); document.write( "and it is the middle of one period of the curve. \n" ); document.write( "------------- \n" ); document.write( "Maybe with that info you can sketch the period centered at pi/3 \n" ); document.write( "and then duplicate that period to the left and to the right. \n" ); document.write( "---------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "---------------------- \n" ); document.write( " \n" ); document.write( " |