document.write( "Question 171418: I need help with solving and graphing one cycle of y= 2sin(3x-pi) and y = -3 cos(1/2x)-4.\r
\n" ); document.write( "\n" ); document.write( "So far for the first question I have gotten really mixed up but I got
\n" ); document.write( "3x-pi =o
\n" ); document.write( "x=pi/3
\n" ); document.write( "x=pi/2
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Algebra.Com's Answer #126614 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
I need help with solving and graphing one cycle of y= 2sin(3x-pi) and y = -3 cos(1/2x)-4.
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\n" ); document.write( "y= 2sin(3x-pi)
\n" ); document.write( "Period = (2/3)pi
\n" ); document.write( "That tells you the distance from peak to peak.
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\n" ); document.write( "Amplitude = 2
\n" ); document.write( "That tells you the height of each peak
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\n" ); document.write( "x-intercept
\n" ); document.write( "2sin(3x-pi) = 0
\n" ); document.write( "sin(3x-pi) = 0
\n" ); document.write( "3x-pi = 0
\n" ); document.write( "x = pi/3
\n" ); document.write( "Mark that point on the x-axis.
\n" ); document.write( "It is the point where the curve crosses the x-axis
\n" ); document.write( "and it is the middle of one period of the curve.
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\n" ); document.write( "Maybe with that info you can sketch the period centered at pi/3
\n" ); document.write( "and then duplicate that period to the left and to the right.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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