document.write( "Question 171369This question is from textbook Precalculus
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document.write( ": Mary has $3.00 in nickels, dimes, and quarters. If she has twice as many dimes as quarters and five more nickels than dimes, how many coins of each type does she have? \n" );
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Algebra.Com's Answer #126596 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .05N+.10D+.25Q=3.00 \n" ); document.write( "D=2Q \n" ); document.write( "N=D+5 OR N=(2Q)+5 \n" ); document.write( ".05(2Q+5)+.10*2Q+.25Q=3.00 \n" ); document.write( ".10Q+.25+.20Q+.25Q=3.00 \n" ); document.write( ".55Q=3.00-.25 \n" ); document.write( ".55Q=2.75 \n" ); document.write( "Q=2.75/.55 \n" ); document.write( "Q=5 NUMBER OF QUARTERS. \n" ); document.write( "D=2*5=10 NUMBER OF DIMES. \n" ); document.write( "N=10+5=15 NUMBER OF NICKLES. \n" ); document.write( "PROOF: \n" ); document.write( ".05*15+.10*10+.25*5=3.00 \n" ); document.write( ".75+1+1.25=3.00 \n" ); document.write( "3.00=3.00 \n" ); document.write( " \n" ); document.write( " |