document.write( "Question 171369This question is from textbook Precalculus
\n" ); document.write( ": Mary has $3.00 in nickels, dimes, and quarters. If she has twice as many dimes as quarters and five more nickels than dimes, how many coins of each type does she have? \n" ); document.write( "
Algebra.Com's Answer #126596 by checkley77(12844)\"\" \"About 
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.05N+.10D+.25Q=3.00
\n" ); document.write( "D=2Q
\n" ); document.write( "N=D+5 OR N=(2Q)+5
\n" ); document.write( ".05(2Q+5)+.10*2Q+.25Q=3.00
\n" ); document.write( ".10Q+.25+.20Q+.25Q=3.00
\n" ); document.write( ".55Q=3.00-.25
\n" ); document.write( ".55Q=2.75
\n" ); document.write( "Q=2.75/.55
\n" ); document.write( "Q=5 NUMBER OF QUARTERS.
\n" ); document.write( "D=2*5=10 NUMBER OF DIMES.
\n" ); document.write( "N=10+5=15 NUMBER OF NICKLES.
\n" ); document.write( "PROOF:
\n" ); document.write( ".05*15+.10*10+.25*5=3.00
\n" ); document.write( ".75+1+1.25=3.00
\n" ); document.write( "3.00=3.00
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