document.write( "Question 171434: Jackie is five years older than her brother. In four years, Jackie will be twice as old as her brother will be. How old is Jackie now? \n" ); document.write( "
Algebra.Com's Answer #126574 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=Jackie's brother's age now; in 4 years he will be x+4 years old \n" ); document.write( "Then x+5=Jackie's age now; in 4 years she will be x+5+4=x+9 years old\r \n" ); document.write( "\n" ); document.write( "Now we are told that: \n" ); document.write( "x+9=2(x+4) get rid of parens (distributive) \n" ); document.write( "x+9=2x+8 subtract x and also 8 from each side \n" ); document.write( "x-x+9-8=2x-x+8-8 collect like terms \n" ); document.write( "1=x or \n" ); document.write( "x=1---------------------Jackie's brother's age now \n" ); document.write( "x+5=1+5=6----------------Jackie's age now \n" ); document.write( "CK \n" ); document.write( "6+4=2*(1+4) \n" ); document.write( "10=10\r \n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor \n" ); document.write( " |