document.write( "Question 171435: Having trouble finding the right formula! How do I solve?\r
\n" ); document.write( "\n" ); document.write( "An express and local train leave Gray's Lake at 3 P.M. and head for Chicago 50 miles away. The express travels twice as fast as the local, and arrives 1 hour ahead of it. Find the speed of each train.
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Algebra.Com's Answer #126567 by Mathtut(3670)\"\" \"About 
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d=rt. we know the distance in both cases is 50. Lets call the local trains rate r and its time t. So the express's rate would be 2r and its time t-1
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\n" ); document.write( "50=rt..........eq 1
\n" ); document.write( "50=2r(t-1).....eq 2
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\n" ); document.write( "lets rewrite eq 1 as t=50/r and plug that value into eq 2
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\n" ); document.write( "\"50=2r%28%2850%2Fr%29-1%29\"----->\"50=2r%28%2850-r%29%2Fr%29\"----
\n" ); document.write( "\"50=2cross%28r%29%2850-r%29%2Fcross%28r%29\"
\n" ); document.write( "\"50=100-2r\"---->\"-2r=-50\"
\n" ); document.write( "\"highlight%28r=25%29\"MPH-speed of the local train
\n" ); document.write( "\"highlight%282%2825%29=50%29\"MPH-speed of the express
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