document.write( "Question 171387: What is the equation of line passing through (2,-3) and (4,-4)?
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Algebra.Com's Answer #126530 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29\" Start with the slope formula.\r
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\n" ); document.write( "\n" ); document.write( "\"m=%28-4--3%29%2F%284-2%29\" Plug in \"y%5B2%5D=-4\", \"y%5B1%5D=-3\", \"x%5B2%5D=4\", and \"x%5B1%5D=2\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=%28-1%29%2F%284-2%29\" Subtract \"-3\" from \"-4\" to get \"-1\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=%28-1%29%2F%282%29\" Subtract \"2\" from \"4\" to get \"2\"\r
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\n" ); document.write( "\n" ); document.write( "So the slope of the line that goes through the points and is \"m=-1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's use the point slope formula:\r
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\n" ); document.write( "\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\" Start with the point slope formula\r
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\n" ); document.write( "\n" ); document.write( "\"y--3=%28-1%2F2%29%28x-2%29\" Plug in \"m=-1%2F2\", \"x%5B1%5D=2\", and \"y%5B1%5D=-3\"\r
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\n" ); document.write( "\n" ); document.write( "\"y%2B3=%28-1%2F2%29%28x-2%29\" Rewrite \"y--3\" as \"y%2B3\"\r
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\n" ); document.write( "\n" ); document.write( "\"y%2B3=%28-1%2F2%29x%2B%28-1%2F2%29%28-2%29\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"y%2B3=%28-1%2F2%29x%2B1\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"2y%2B6=-x%2B2\" Multiply EVERY term by the LCD 2 to clear the fraction.\r
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\n" ); document.write( "\n" ); document.write( "\"2y%2B6%2Bx=2\" Add \"x\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"2y%2Bx=2-6\" Subtract 6 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B2y=-4\" Combine and rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "So the line that passes through (2,-3) and (4,-4) is \"x%2B2y=-4\"
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