document.write( "Question 171381: Algebraically determine the EXACT roots in simplest form for:
\n" ); document.write( "a) (5/x-3)=(x/x+1)
\n" ); document.write( "b) 3x-2=(-13/x+4)
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Algebra.Com's Answer #126529 by stanbon(75887)\"\" \"About 
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Algebraically determine the EXACT roots in simplest form for:
\n" ); document.write( "a) (5/x-3)=(x/x+1)
\n" ); document.write( "Cross-multiply to get:
\n" ); document.write( "5(x+1) = x(x-3)
\n" ); document.write( "5x+5 = x^2-3x
\n" ); document.write( "x^2-8x-5 = 0
\n" ); document.write( "x = [8 +- sqrt(64-4*-5)]/2
\n" ); document.write( "x = [8 +- sqrt(84)]/2
\n" ); document.write( "x = [8 +- 2sqrt(21)]/2
\n" ); document.write( "x = 4 +- sqrt(21)
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\n" ); document.write( "\n" ); document.write( "b) 3x-2=(-13/x+4)
\n" ); document.write( "(3x-2)(x+4)+13 = 0
\n" ); document.write( "3x^2+10x+5 = 0
\n" ); document.write( "x= [-10 +- sqrt(100-4*3*5)]/6
\n" ); document.write( "x= [-10 +- sqrt(40)]/6\r
\n" ); document.write( "\n" ); document.write( "x = [-10 +- 2sqrt(10)]/6\r
\n" ); document.write( "\n" ); document.write( "x = [(-5/3) +- (1/3)sqrt(10)]
\n" ); document.write( "==================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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