document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=171362>Question 171362</A>: <I><SPAN STYLE=\"word-break: break-all;\"> When trying to decide if an ordered pair is a solution of a system of liner equation if the x is already negative and the x value given is also negative would it turn positive or stay negative?\r<BR>\n" );
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document.write( "Ex: (-9,5)<BR>\n" );
document.write( "      -x + 3y = 24 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #126511 by </B><A HREF=/tutors/aboutme.mpl?userid=gonzo><B>gonzo(654)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=gonzo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=126511\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ordered pair: (-9,5)<BR>\n" );
document.write( "equation: -x + 3y = 24<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "you substitute -9 for x and 5 for y<BR>\n" );
document.write( "-x + 3y = 24 becomes:<BR>\n" );
document.write( "-(-9) + 3(5) = 24<BR>\n" );
document.write( "this becomes:<BR>\n" );
document.write( "9 + 15 = 24<BR>\n" );
document.write( "24 = 24<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "the -x in the equation is - (x)<BR>\n" );
document.write( "you are substituting for x, not -x<BR>\n" );
document.write( "it becomes - (-9)<BR>\n" );
document.write( "which then becomes + because a minus of a minus is a plus.<BR>\n" );
document.write( "-----<BR>\n" );
document.write( " </SPAN>\n" );
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