document.write( "Question 171363: I apologize if this is in the wrong heading. My problem is systems of linear equation by substitution. { y=4x { y=2x+6\r
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Algebra.Com's Answer #126508 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
This is a \"systems of linear equations\" problem, but that's ok.\r
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\n" ); document.write( "\n" ); document.write( "\"y=2x%2B6\" Start with the second equation\r
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\n" ); document.write( "\n" ); document.write( "\"4x=2x%2B6\" Plug in \"y=4x\" (the first equation). What's going on here is we're simply replacing \"y\" with \"4x\". This is where the \"substitution\" comes in.\r
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\n" ); document.write( "\n" ); document.write( "\"4x-2x=6\" Subtract \"2x\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"2x=6\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%286%29%2F%282%29\" Divide both sides by \"2\" to isolate \"x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=3\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "So the first part of the answer is \"x=3\" \r
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\n" ); document.write( "\n" ); document.write( "\"y=4x\" Go back to the first equation.\r
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\n" ); document.write( "\n" ); document.write( "\"y=4%283%29\" Plug in \"x=3\" (the previous solution)\r
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\n" ); document.write( "\n" ); document.write( "\"y=12\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "So the second part of the answer is \"y=12\" \r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x=3\" and \"y=12\" which form the ordered pair (3,12)
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