document.write( "Question 171363: I apologize if this is in the wrong heading. My problem is systems of linear equation by substitution. { y=4x { y=2x+6\r
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document.write( "I am not sure how to do this problem. I tried getting the numbers to match up so i could figure it out, but i cant seem to grasp it. Sorry if you cannot solve this problem and i'm sorry for wasting your time, but i am about ready to give up. This is a worksheet, and not from a book, by the way.
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Algebra.Com's Answer #126507 by gonzo(654)![]() ![]() ![]() You can put this solution on YOUR website! your 2 equations are: \n" ); document.write( "y = 4x \n" ); document.write( "y = 2x+6 \n" ); document.write( "since both equations equal to y, then they both must be equal to each other. \n" ); document.write( "so....... \n" ); document.write( "4x = 2x + 6 \n" ); document.write( "----- \n" ); document.write( "this is the same as saying substitute 4x for y in the second equation because y = 4x from the first equation. \n" ); document.write( "----- \n" ); document.write( "4x = 2x + 6 \n" ); document.write( "simplify: \n" ); document.write( "2x = 6 \n" ); document.write( "x = 3 \n" ); document.write( "----- \n" ); document.write( "now you have x, you can solve for y. \n" ); document.write( "in the first equation. \n" ); document.write( "y = 4x \n" ); document.write( "y = 4*3) \n" ); document.write( "y = 12 \n" ); document.write( "----- \n" ); document.write( "in the second equation. \n" ); document.write( "y = 2x + 6 \n" ); document.write( "y = 2*3 + 6 \n" ); document.write( "y = 6 + 6 \n" ); document.write( "y = 12 \n" ); document.write( "----- \n" ); document.write( "you get the same value of y and x in both equation so you have solved them simultaneously. \n" ); document.write( "x = 3 \n" ); document.write( "y = 12 \n" ); document.write( "----- \n" ); document.write( " \n" ); document.write( " |