document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=171334>Question 171334</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the cos 0 (theta) if csc 0(theta) = 11 square root of 2 divided by 12.  (I don't have the symbols on my computer to write this exactly like on the page, but it is 11 by square root of two, over 12).   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #126483 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=126483\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the cos (theta) if csc theta) = 11 square root of 2 divided by 12<BR>\n" );
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document.write( "General Form: csc(theta) = r/y<BR>\n" );
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document.write( "Your Problem:<BR>\n" );
document.write( "csc(theta) = [11sqrt(2)]/12 , so  r = 11sqrt(2) and y = 12<BR>\n" );
document.write( "Find x: x = sqrt(r^2-y^2) = sqrt[121*2 + 144] = sqrt(386)<BR>\n" );
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document.write( "Since cos(theta) = x/r, cos(theta) = sqrt(386)/11sqrt(2) = sqrt(193)/11<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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