document.write( "Question 171304: i am a three digit number less than 200. i am divisible by 9 and 12 .my units digit is less than my ten digit .what am I \n" ); document.write( "
Algebra.Com's Answer #126466 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! to be divisible by 9 the digits added together must be divisible by 9 and to be divisible by 12 it must be even.\r \n" ); document.write( "\n" ); document.write( "along with units digit being < tens digit....let see if we can come up with something.\r \n" ); document.write( "\n" ); document.write( "ones unit must be 0,2,4,6,or 8. \r \n" ); document.write( "\n" ); document.write( "if 0 then tens unit can be 1-9 case1 \n" ); document.write( "if 2 then tens unit can be 3-9 case2 \n" ); document.write( "if 4 then tens unit can be 5-9 case3 \n" ); document.write( "if 6 then tens unit can be 7-9 case4 \n" ); document.write( "if 8 then tens unit can be 9 case5 \n" ); document.write( ": \n" ); document.write( "108 is covered in case1 because 0<8 \n" ); document.write( ": \n" ); document.write( "lets work backwards \n" ); document.write( ": \n" ); document.write( "case5: 98----9+8=17 to be divisible by 9 hunderds unit has to be 1 and 198 \n" ); document.write( " is not divisible by 12 \n" ); document.write( ": \n" ); document.write( "case4:96,86,76...96---9+6=16 to be div by 9 100's unit has to be 3 and that is more than 200. 86 ...8+6=14 to be div by 9 100's unit has to be 4....to big \n" ); document.write( "same problem with 76 \n" ); document.write( ": \n" ); document.write( "case3:94,84,74,64,54...9+4, 8+4,7+4,6+4,5+4 all present problems with #'s larger than 200 \n" ); document.write( ": \n" ); document.write( "case2:92,82,72,62,52,42,32 ...92,82,and 72 all get throw out because #'s larger than 200. 62 is 6+2=8..to be divisble by 9 100's unit must be 1...162..not divisible by 12 take 52,42,32 end up with being over 200 \n" ); document.write( ": \n" ); document.write( "case1:90,80,70,60,50,40,30,20,10... 90 larger than 200...80 is 8+0=8 in order to be divisible by 9 100's unit has to be 1. 180.......guess what this number is divisible by 9 and 12 and is less than 200 \n" ); document.write( "applying divisibility rules for the rest of the numbers in this case make all the numbers to large >200 \n" ); document.write( ": \n" ); document.write( "SO WE HAVE GONE THROUGH ALL THE CASES AND 180 is the only one that qualified \n" ); document.write( "there could be a simpler way but I will have to think on that \n" ); document.write( " |