document.write( "Question 171298This question is from textbook Algebra 1
\n" ); document.write( ": The sum of three numbers is 123. The second number is 9 less than two times the first number. The third number is 6 more than three times the first number. Find the three numbers. \n" ); document.write( "
Algebra.Com's Answer #126462 by KnightOwlTutor(293)\"\" \"About 
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x=1rst #
\n" ); document.write( "2x-9=2nd #
\n" ); document.write( "3x+6=3rd #\r
\n" ); document.write( "\n" ); document.write( "x+2x-9+3x+6=123\r
\n" ); document.write( "\n" ); document.write( "Combine like terms and simplify\r
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\n" ); document.write( "\n" ); document.write( "6x-3=123\r
\n" ); document.write( "\n" ); document.write( "Add 3 to both sides\r
\n" ); document.write( "\n" ); document.write( "6x=126\r
\n" ); document.write( "\n" ); document.write( "x=21\r
\n" ); document.write( "\n" ); document.write( "21=1rst #\r
\n" ); document.write( "\n" ); document.write( "33=2nd #\r
\n" ); document.write( "\n" ); document.write( "69=3rd #\r
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