document.write( "Question 171311: I need a little help trying to figure out this proble it is on how to find specified values of functions.. So here is my question..
\n" ); document.write( "Find f(2) given f(x) = -2x to the third power + x two the second power +23 That is my question...
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Algebra.Com's Answer #126461 by gonzo(654)\"\" \"About 
You can put this solution on YOUR website!
f(x) = \"-2%2Ax%5E3+%2B+x%5E2+%2B+23\"
\n" ); document.write( "is what i think you said.
\n" ); document.write( "no matter.
\n" ); document.write( "the procedure is the same.
\n" ); document.write( "if
\n" ); document.write( "f(x) = \"-2%2Ax%5E3+%2B+x%5E2+%2B+23\"
\n" ); document.write( "then,
\n" ); document.write( "in order to find f(2), you have to substitute (2) for (x) in the equation.
\n" ); document.write( "your equation starts out as:
\n" ); document.write( "f(x) = \"-2%2Ax%5E3+%2B+x%5E2+%2B+23\"
\n" ); document.write( "you substitute (2) for (x) to get:
\n" ); document.write( "f(2) = \"-2%2A%282%29%5E3+%2B+%282%29%5E2+%2B+23\"
\n" ); document.write( "simplify:
\n" ); document.write( "f(2) = \"-2%2A%288%29+%2B+4+%2B+23\"
\n" ); document.write( "f(2) = \"-16+%2B+4+%2B+23\"
\n" ); document.write( "f(2) = 11
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\n" ); document.write( "if i didn't get your equation right, just follow the same procedure and you'll get your answer.
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