document.write( "Question 171301: 2x-3y=-14
\n" ); document.write( "y=4x+8\r
\n" ); document.write( "\n" ); document.write( "solve this system of equations by substitution
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Algebra.Com's Answer #126454 by checkley77(12844)\"\" \"About 
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2x-3y=-14
\n" ); document.write( "y=4x+8
\n" ); document.write( "2x-3(4x+8)=-14
\n" ); document.write( "2x-12x-24=-14
\n" ); document.write( "2x-12x-24+14=0
\n" ); document.write( "-10x-10=0
\n" ); document.write( "-10x=10
\n" ); document.write( "x=10/-10
\n" ); document.write( "x=-1 ans.
\n" ); document.write( "2*-1-3y=-14
\n" ); document.write( "-2-3y=-14
\n" ); document.write( "-3y=-14+2
\n" ); document.write( "-3y=-12
\n" ); document.write( "y=-12/-3
\n" ); document.write( "y=4 ans.
\n" ); document.write( "Proof:
\n" ); document.write( "4=4*-1+8
\n" ); document.write( "4=-4+8
\n" ); document.write( "4=4
\n" ); document.write( "
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