document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=171207>Question 171207</A>: <I><SPAN STYLE=\"word-break: break-all;\"> #1.$480 at 10% compounded quarterly for 5 years\r<BR>\n" );
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document.write( "#2. $800 at 2% compounded continuously for 8 years </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #126441 by </B><A HREF=/tutors/aboutme.mpl?userid=midwood_trail><B>midwood_trail(310)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=midwood_trail><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=126441\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You need the formula\r<BR>\n" );
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document.write( "A = Pe^(rt)\r<BR>\n" );
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document.write( "A = final amount\r<BR>\n" );
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document.write( "P = principal or original amount\r<BR>\n" );
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document.write( "r = rate of interest per year\r<BR>\n" );
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document.write( "t = time (in years)\r<BR>\n" );
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document.write( "I will set up both equations and let you do the math.\r<BR>\n" );
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document.write( "If you cannot, then write back.\r<BR>\n" );
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document.write( "#1.$480 at 10% compounded quarterly for 5 years\r<BR>\n" );
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document.write( "A = 480e^(0.10)(5)...Solve for A\r<BR>\n" );
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document.write( "#2. $800 at 2% compounded continuously for 8 years\r<BR>\n" );
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document.write( "A = 800e^(0.02)(8)...Solve for A\r<BR>\n" );
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document.write( "Can you take it from here?\r<BR>\n" );
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document.write( " </SPAN>\n" );
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