document.write( "Question 171223: This is a General Factoring Section...\r
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\n" ); document.write( "\n" ); document.write( "y(2y+7)=15
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Algebra.Com's Answer #126406 by scott8148(6628)\"\" \"About 
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2y^+7y=15\r
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\n" ); document.write( "\n" ); document.write( "subtracting 15 __ 2y^2+7y-15=0\r
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\n" ); document.write( "\n" ); document.write( "factoring __ (2y-3)(y+5)=0\r
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\n" ); document.write( "\n" ); document.write( "2y-3=0 __ y=3/2\r
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\n" ); document.write( "\n" ); document.write( "y+5=0 __ y=-5
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