document.write( "Question 2688: Use the equation y=x(squared)-3x-10\r
\n" ); document.write( "\n" ); document.write( "-compared to the graph of y=-3x(squared), does this graph open in the same direction or opposite?\r
\n" ); document.write( "\n" ); document.write( "-find x-intercepts for the graph\r
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\n" ); document.write( "could you please answer as soon as possible and please explain how you got your answer and why it is correct...thank you so much!
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Algebra.Com's Answer #1264 by khwang(438)\"\" \"About 
You can put this solution on YOUR website!
y=x^2-3x-10 -compared to the graph of y=-3x^2,
\n" ); document.write( " does this graph open in the same direction or opposite?
\n" ); document.write( " -find x-intercepts for the graph
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\n" ); document.write( " At first you should know how to type the squares correctly.\r
\n" ); document.write( "\n" ); document.write( " Use complete square to y=x^2-3x-10, we have
\n" ); document.write( " y = (x-3/2)^2 -10 -9/4 = (x-3/2)^2 -49/4 or
\n" ); document.write( " y + 49/4 = (x-3/2)^2
\n" ); document.write( " So, this parabola has vertex (3/2,-49/4) and open upward (since (x-3/2)^2 >=0)
\n" ); document.write( " Another graph y=-3x^2 has vertex (0,0) and open downward (since -3x^2 <=0)\r
\n" ); document.write( "\n" ); document.write( " Also, set y=0, in y=x^2-3x-10 =0,
\n" ); document.write( " By factoring x^2-3x-10 = (x-5)(x+2) =0, we have x=5 or -2.
\n" ); document.write( " So, y=x^2-3x-10 has two x-intercepts 5 ,-2.\r
\n" ); document.write( "\n" ); document.write( " Clearly, set y=0, in y=-3x^2, we have the x-intercept =0.\r
\n" ); document.write( "\n" ); document.write( " Graphs as below:\r
\n" ); document.write( "\n" ); document.write( " \"+graph%28+300%2C+200%2C+-2%2C+6%2C+-12%2C+5%2C+x%5E2-3x-10%2C+-3x%5E2%29+\"
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