document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=171175>Question 171175</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone please show me how to do this problem<BR>\n" );
document.write( "Prove that the statement: 1/5+1/5^2+1/5^3+...+1/5^n=1/491-1/5^n) is true for all positive integers n.  Show all your work<BR>\n" );
document.write( "PLEASE HELP!!!!!<BR>\n" );
document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #126380 by </B><A HREF=/tutors/aboutme.mpl?userid=oscargut><B>oscargut(2103)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oscargut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=oscargut><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=126380\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> S=1/5+1/5^2+1/5^3+...+1/5^n<BR>\n" );
document.write( "(1/5)S=1/5^2+1/5^3+...+1/5^n+1/5^(n+1)\r<BR>\n" );
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document.write( "S-(1/5)S = (4/5)S = 1/5 - (1/5)^(n+1)\r<BR>\n" );
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document.write( "S=1/4 - (5/4)(1/5)^(n+1)= 1/4(1-(1/5)^n)\r<BR>\n" );
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document.write( "i think you typed a 9 instead of a (<BR>\n" );
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