document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=23918>Question 23918</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle garden is 3ft less than 2 times it's width. If the perimeter of the garden is 54ft, find the dimension of a garden. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #12636 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=12636\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Length = 2x-3<BR>\n" );
document.write( "width = x<BR>\n" );
document.write( "Perimeter = 54\r<BR>\n" );
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document.write( "SInce the formula for P is 2(l+w)=P\r<BR>\n" );
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document.write( "We plug that in.<BR>\n" );
document.write( "2(2x-3+x)=54<BR>\n" );
document.write( "6x-6=54<BR>\n" );
document.write( "6x=60<BR>\n" );
document.write( "x=10\r<BR>\n" );
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document.write( "2(10)-3=17\r<BR>\n" );
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document.write( "Hence the width is 10cm and the length is 17cm.<BR>\n" );
document.write( "Paul. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );