document.write( "Question 171127: log 3 x= log 5 + log (x-4) \n" ); document.write( "
Algebra.Com's Answer #126322 by solver91311(24713)\"\" \"About 
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Remember, the sum of the logs is the log of the product, or \"log%28b%2C%28a%29%29%2Blog%28b%2C%28c%29%29=log%28b%2C%28ac%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "So,\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%283x%29%29=log%2810%2C%285%29%29%2Blog%2810%2C%28x-4%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%283x%29%29=log%2810%2C%285%28x-4%29%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "but if \"log%28b%2C%28a%29%29=log%28b%2C%28c%29%29\" then \"a=c\" so:\r
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\n" ); document.write( "\n" ); document.write( "\"3x=5%28x-4%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"3x=5x-20\"\r
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\n" ); document.write( "\n" ); document.write( "\"-2x=-20\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=10\"\r
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