document.write( "Question 171112: 2x^2-2x+7=0 \r
\n" ); document.write( "\n" ); document.write( "I have to solve this by completing the square. I solved it but I'm unsure of my answer, I got x= 1/2 + or - i times radical 13 over 2.
\n" ); document.write( "

Algebra.Com's Answer #126321 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
Complete the square on \"2x%5E2-2x%2B7=0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Step 1, starting from a quadratic in standard form like you have is to put the constant term on the right:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2x%5E2-2x=-7\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Step 2, if the coefficient on the \"x%5E2\" term is other than 1, divide by that coefficient.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5E2-x=-7%2F2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Step 3, divide the resulting coefficient on the \"x\" term by 2 and square the result\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28%28-1%29%2F2%29%5E2=1%2F4\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Step 4, add this result to both sides of your equation and collect terms\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5E2-x%2B1%2F4=-7%2F2%2B1%2F4\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5E2-x%2B1%2F4=-13%2F4\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Step 5, the above result has a perfect square on the left (hence the term \"completing the square\"), so factor it:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28x-1%2F2%29%5E2=-13%2F4\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Step 6, take the square root of both sides:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x-1%2F2=sqrt%28-13%2F4%29\" or \"x-1%2F2=-sqrt%28-13%2F4%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Which leads us to a great big oops! because you can't take the square root of a negative number. The solution is to use the imaginary number \"i\" which is defined as \"i%5E2=-1\", leaving us with:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x-1%2F2=sqrt%28%28-1%2913%2F4%29\" or \"x-1%2F2=-sqrt%28%28-1%2913%2F4%29\"
\n" ); document.write( "\"x-1%2F2=sqrt%28-1%29%2Asqrt%2813%2F4%29\" or \"x-1%2F2=-sqrt%28-1%29%2Asqrt%2813%2F4%29\"
\n" ); document.write( "\"x-1%2F2=i%2Asqrt%2813%2F4%29\" or \"x-1%2F2=-i%2Asqrt%2813%2F4%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Step 7, isolate \"x\" and simplify in each equation\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5B1%5D=1%2F2%2Bi%2Asqrt%2813%2F4%29=%281%2Bi%2Asqrt%2813%29%29%2F2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5B2%5D=1%2F2-i%2Asqrt%2813%2F4%29=%281-i%2Asqrt%2813%29%29%2F2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If you want the exact representation of the roots of the given equation, you are done. If you need a numerical approximation of the imaginary parts of your complex numbers, get out your calculator.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Multiplying \"+%28x-%28%281%2Bi%2Asqrt%2813%29%29%2F2%29%29%28x-%28%281-i%2Asqrt%2813%29%29%2F2%29%29\" to verify that the product is, in fact, \"2x%5E2-2x%2B7\", is left as an exercise for the student. Alternatively, you could just trust me.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );