document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=171069>Question 171069</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive odd integers such that three times the second minus the third is 11 more than the first.\r<BR>\n" );
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document.write( "This is what I have, 2x+1, 2x+3, 2x+5, but from there I need help please.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #126301 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=126301\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well, that's a good start!<BR>\n" );
document.write( "Three times the second can be expressed as: 3(2x+3)<BR>\n" );
document.write( "Eleven more than the first can be expressed as: (2x+1)+11<BR>\n" );
document.write( "So, putting it all together, you get:<BR>\n" );
document.write( "3(2x+3)-(2x+5) = (2x+1)+11 Simplify this to solve for x.<BR>\n" );
document.write( "6x+9-2x-5 = 2x+12 Combine like-terms.<BR>\n" );
document.write( "4x+4 = 2x+12 Subtract 2x from both sides.<BR>\n" );
document.write( "2x+4 = 12 Subtract 4 from both sides.<BR>\n" );
document.write( "2x = 8 Divide both sides by 2.<BR>\n" );
document.write( "x = 4, so...<BR>\n" );
document.write( "2x+1 = 8+1 = 9<BR>\n" );
document.write( "2x+3 = 8+3 = 11<BR>\n" );
document.write( "2x+5 = 8+5 = 13<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "3(11)-13 = 9+11<BR>\n" );
document.write( "33-13 = 20<BR>\n" );
document.write( "20 = 20 OK! </SPAN>\n" );
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