document.write( "Question 171089: the current in a stream moves at a speed of 10 mph. A boat travels 29 miles upstreamand 29 miles downstream in a total time of 8 hours. What is the speed of the boat in still water \n" ); document.write( "
Algebra.Com's Answer #126295 by checkley77(12844)\"\" \"About 
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29/(B-10)+29/(B+10)=8
\n" ); document.write( "(29(B+10)+29(B-10))/(B-10)(B+10)=8
\n" ); document.write( "29B+290+29B-290=8(B^2-100)
\n" ); document.write( "58B=8B^2-800
\n" ); document.write( "8B^2-58B-800=0
\n" ); document.write( "USING THE QUADRATIC EQUATION:\"B+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"WE GET:
\n" ); document.write( "B=(58+-SQRT[-58^2-4*8*-800])/2*8
\n" ); document.write( "B=(58+-SQRT[3,364+25,600])/16
\n" ); document.write( "B=(58+-SQRT28,964)/16
\n" ); document.write( "B=(58+-170.18813)/16
\n" ); document.write( "B=(58+170.18813)/16
\n" ); document.write( "B=228.18813/16
\n" ); document.write( "B=14.261758 mph IS THE SPEED OF THE BOAT.
\n" ); document.write( "PROOF:
\n" ); document.write( "29/(14.261758-10)+29/(14.261758+10)=8
\n" ); document.write( "29/4.261758+29/24.261758=8
\n" ); document.write( "6.805+1.195
\n" ); document.write( "8=8
\n" ); document.write( " \n" ); document.write( "
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