document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=171029>Question 171029</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cars leave from New York and drive in opposite directions (north and south).  The car going north travels at 60 mph.  The car going south leaves an hour and a half after the first and goes 80 mph.  At what time will the cars be 620 miles apart?  This is a homework problem on a sheet of paper so not from a book.  I tried it and got 32 hours 30 minutes but I don't think that it's right. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #126260 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=126260\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LET 60*T= THE NORTH CAR.<BR>\n" );
document.write( "LET 80(T-1.5)= THE SOUTH CAR. <BR>\n" );
document.write( "60T+80(T-1.5)=620<BR>\n" );
document.write( "60T+80T-120=620<BR>\n" );
document.write( "140T=620+120<BR>\n" );
document.write( "140T=740<BR>\n" );
document.write( "T=740/140<BR>\n" );
document.write( "T=5.2857 HOURS AFTER THE CAR GOING NORTH STARTED THEY WILL BE 620 MILES APART<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "60*5.2857+80(5.2857-1.5)=620<BR>\n" );
document.write( "317.14285+80*3.7857=620<BR>\n" );
document.write( "317.14285+302.856=620<BR>\n" );
document.write( "620~620 \r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );