document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=171033>Question 171033</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cars leave from Ohio and go in opposite directions.  One car goes west at 60 mph.  Another goes east at 80 mph but leaves 1 hour 30 min after the first car.  At what time will they be 620 miles apart?  This isn't from a book.  I am completely stumped with no idea how to do this. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #126259 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=126259\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LET 60*T= THE WEST CAR.<BR>\n" );
document.write( "LET 80(T-1.5)= THE EAST CAR.  <BR>\n" );
document.write( "60T+80(T-1.5)=620<BR>\n" );
document.write( "60T+80T-120=620<BR>\n" );
document.write( "140T=620+120<BR>\n" );
document.write( "140T=740<BR>\n" );
document.write( "T=740/140<BR>\n" );
document.write( "T=5.2857 HOURS AFTER THE CAR GOING WEST STARTED THEY WILL BE 620 MILES APART<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "60*5.2857+80(5.2857-1.5)=620<BR>\n" );
document.write( "317.14285+80*3.7857=620<BR>\n" );
document.write( "317.14285+302.856=620<BR>\n" );
document.write( "620~620\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );