document.write( "Question 171037: You are 4 years older than your brother. Two years ago you were 1.5 x older than him. How old are you know? \n" ); document.write( "
Algebra.Com's Answer #126249 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
I think you meant to say \"How old are you now?\"\r
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\n" ); document.write( "\n" ); document.write( "You are x years old now.\r
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\n" ); document.write( "\n" ); document.write( "Your brother is then x - 4 years old now.\r
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\n" ); document.write( "\n" ); document.write( "Two years ago, you were x - 2 years old, and your brother was x - 4 - 2 or x - 6 years old.\r
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\n" ); document.write( "\n" ); document.write( "Your age two years ago (x - 2) is 1.5 times your brothers age two years ago, or 1.5(x - 6). So you can write:\r
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\n" ); document.write( "\n" ); document.write( "\"x-2+=+1.5%28x-6%29\"\r
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\n" ); document.write( "\n" ); document.write( "Solve the equation for x to get your age now. Once you have solved the equation, check your work: Subtract 4 from your answer to get your brother's age now. Then subtract 2 from each of yours and your brother's ages to get the ages two years ago. Verify that your age 2 years ago is one and one-half times your brother's age 2 years ago. \r
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