document.write( "Question 170998: 3^x-2 = 1/9\r
\n" ); document.write( "\n" ); document.write( "So far I have x-2 log 3 = log 1/9
\n" ); document.write( "I am not sure if this is even correct.
\n" ); document.write( "thanks \n" ); document.write( "

Algebra.Com's Answer #126239 by jojo14344(1513) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"3%5E%28x-2%29=+1%2F9\"$
\n" ); document.write( "You're on the right track amigo,
\n" ); document.write( "becomes,
\n" ); document.write( " $\"%28x-2%29log3=log%281%2F9%29\"$
\n" ); document.write( " $\"x-2=log%281%2F9%29%2Flog3\"$
\n" ); document.write( " $\"x-2=-2\"$
\n" ); document.write( " $\"x=-2%2B2=highlight%280=x%29\"$ , Answer
\n" ); document.write( "Check it out:
\n" ); document.write( " $\"3%5E%280-2%29=1%2F9\"$
\n" ); document.write( " $\"3%5E-2=1%2F9\"$
\n" ); document.write( " $\"1%2F3%5E2=1%2F9\"$
\n" ); document.write( " $\"1%2F9=1%2F9\"$
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
\n" ); document.write( " \n" ); document.write( "

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