document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=170967>Question 170967</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this problem by using the distrubutive property:<BR>\n" );
document.write( "     5(x-3)+4(x+3)=3(x-1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #126221 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=126221\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> distribution property states that a(b+c)=ab+ac<BR>\n" );
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document.write( "5(x-3)=5x-15<BR>\n" );
document.write( "4(x+3)=4x+12<BR>\n" );
document.write( "3(x-1)=3x-3<BR>\n" );
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document.write( "5x-15+4x+12=3x-3........now combine like terms so that x is on one side of the equation and constants on the other<BR>\n" );
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document.write( "9x-3=3x-3---->subtract 3x and add 3 to each side<BR>\n" );
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document.write( "6x=0<BR>\n" );
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