document.write( "Question 170955This question is from textbook Introductory Algebra
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document.write( ": Sue walks and jogs to school. She walks at a speed of 5kmh and jogs at a speed of 9kmh. It is 8km to school. She makes it in 1 hour. How far does she jog?\r
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document.write( "I know that d=rt but I'm drawing a blank on this one.\r
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document.write( "Thanks \n" );
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Algebra.Com's Answer #126214 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! ok.......this isnt written very well but what they are getting at is she walked a portion and jogged a portion of the trip(8km) to school. d=rt. lets call the distance she walked x and the distance she jogged 8-x. lets the time she walked t and the time she jogged 1-t(1hour altogether). walking rate is 5 and jogging rate is 9 \n" ); document.write( ": \n" ); document.write( "x=5t.........eq 1 \n" ); document.write( "8-x=9(1-t)...eq 2 \n" ); document.write( ": \n" ); document.write( "take x's value from eq 1 and plug it into eq 2 \n" ); document.write( ": \n" ); document.write( "8-5t=9(1-t) \n" ); document.write( ": \n" ); document.write( "8-5t=9-9t \n" ); document.write( ": \n" ); document.write( "4t=1 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "we are after distance she jogged so lets find x ...x=5(1/4)=5/4=1.25..distance she walked \n" ); document.write( ": \n" ); document.write( "distance she jogged is 8-x... |