document.write( "Question 170955This question is from textbook Introductory Algebra
\n" ); document.write( ": Sue walks and jogs to school. She walks at a speed of 5kmh and jogs at a speed of 9kmh. It is 8km to school. She makes it in 1 hour. How far does she jog?\r
\n" ); document.write( "\n" ); document.write( "I know that d=rt but I'm drawing a blank on this one.\r
\n" ); document.write( "\n" ); document.write( "Thanks
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Algebra.Com's Answer #126210 by angel1286(3)\"\" \"About 
You can put this solution on YOUR website!
just set up an equation that adds up the distances traveled:
\n" ); document.write( "let x denote the time that it was used walking, then the time for joging cam be denoted as (1-x) because it was one hour of total trip, then use the formula that distance = velocity * time; then the equation looks like:\r
\n" ); document.write( "\n" ); document.write( "\"+5x+%2B+9%2A%281-x%29=8+\"
\n" ); document.write( "\"5x+%2B+9+-+9x+=+8\"
\n" ); document.write( "\"+-4x+%2B+9+=+8\"
\n" ); document.write( "\"-4x=-1\"
\n" ); document.write( "\"x=.25\" then to find out how much she jogs, we multiply 9 * (1-0.25) because that is the time used for joggin and the answer is 6.75
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