document.write( "Question 170900: Joe bought a used motorcycle for $600. He spent $54 fixing it. He advertised the bike for sale for 70% more than he paid originally. The bike didn't sell so he marked the price down 20%. The bike sold. How much money did Joe make?\r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "THANK YOU SO MUCH! \n" );
document.write( "
Algebra.Com's Answer #126193 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! Lets start out with a general equation calling the original price paid x....we know that x =600 dollars. 70%(.7) times x added to the original price x is the new price. x+.7x=1.7x. But Joe decided to mark this new price down 20%(.2) so we mark down the new price by 20% with this equation 1.7x(.2) is the mark down and we subtract this from the new price. \n" ); document.write( ": \n" ); document.write( "so we have new price 1.7x and markdown 1.7x(.2). \n" ); document.write( ": \n" ); document.write( "1.7x-1.7x(.2)=sales price (we will call this s). \n" ); document.write( ": \n" ); document.write( "we know x=600 so plug in this value for x. \n" ); document.write( ": \n" ); document.write( "1.7(600)-1.7(600)(.2)=s \n" ); document.write( ": \n" ); document.write( "1020-204=s \n" ); document.write( ": \n" ); document.write( "s=816 \n" ); document.write( ": \n" ); document.write( "now in order to get what Joe made on this we take s-(x)-(expenses)=profit(p) \n" ); document.write( ": \n" ); document.write( "816-600-54=p \n" ); document.write( ": \n" ); document.write( " |