document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=23902>Question 23902</A>: <I><SPAN STYLE=\"word-break: break-all;\"> bess has $2.80 in quarters and dimes. the number of dime is 7 less than the number of quarters. Find the number she has of each kind.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #12618 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=12618\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the dimes be d<BR>\n" );
document.write( "Let the quarters be x\r<BR>\n" );
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document.write( "d = x-7<BR>\n" );
document.write( "Dime value = 0.1 x 100 = 10<BR>\n" );
document.write( "Quarter value = 0.25 x 100 = 25<BR>\n" );
document.write( "total = 2.80 x 100 = 280\r<BR>\n" );
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document.write( "10d+25x=280<BR>\n" );
document.write( "10(x-7)+25x=280<BR>\n" );
document.write( "10x-70+25x=280<BR>\n" );
document.write( "35x=350<BR>\n" );
document.write( "x = 10\r<BR>\n" );
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document.write( "d = 10-7<BR>\n" );
document.write( "d=3\r<BR>\n" );
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document.write( "Hence, there are 10 quarters and 3 dimes. <BR>\n" );
document.write( "Paul. </SPAN>\n" );
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