document.write( "Question 170922: Solve the equation for x in the interval 0≤x ≤2 π:\r
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document.write( "2sin²x-sinx-1=0
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Algebra.Com's Answer #126176 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Solve the equation for x in the interval 0≤x ≤2 π: \n" ); document.write( "2sin²x-sinx-1=0\r \n" ); document.write( "\n" ); document.write( "Factor to get: \n" ); document.write( "(2sinx+1)(sinx-1) = 0\r \n" ); document.write( "\n" ); document.write( "sinx = -1/2 or sinx = 1\r \n" ); document.write( "\n" ); document.write( "x = (11/6)pi or (7/6)pi or pi/4 or (3/4)pi \n" ); document.write( "============================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |