document.write( "Question 170922: Solve the equation for x in the interval 0≤x ≤2 π:\r
\n" ); document.write( "\n" ); document.write( "2sin²x-sinx-1=0
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Algebra.Com's Answer #126176 by stanbon(75887)\"\" \"About 
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Solve the equation for x in the interval 0≤x ≤2 π:
\n" ); document.write( "2sin²x-sinx-1=0\r
\n" ); document.write( "\n" ); document.write( "Factor to get:
\n" ); document.write( "(2sinx+1)(sinx-1) = 0\r
\n" ); document.write( "\n" ); document.write( "sinx = -1/2 or sinx = 1\r
\n" ); document.write( "\n" ); document.write( "x = (11/6)pi or (7/6)pi or pi/4 or (3/4)pi
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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