document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=170915>Question 170915</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If cos &#952;=-5/13 and 0&#8804;x &#8804;2 &#960;, determine:\r<BR>\n" );
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document.write( "a) tan &#952;<BR>\n" );
document.write( "b) sec &#952;<BR>\n" );
document.write( "c) the possible values of &#952; to the nearest tenth<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #126174 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=126174\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If cos &#952;=-5/13 and 0&#8804;x &#8804;2 &#960;, determine:<BR>\n" );
document.write( "Since cos = x/5, x = -5 and r = 13<BR>\n" );
document.write( "Then y = sqrt(r^2-x^2) = 12  or -12<BR>\n" );
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document.write( "a) tan &#952; = y/x = +12/13 or -12/13<BR>\n" );
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document.write( "b) sec &#952; = r/x = 13/-5 <BR>\n" );
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document.write( "c) the possible values of &#952; to the nearest tenth<BR>\n" );
document.write( "theta = inversetan(-12/13) = 180 - 42.7 = 137.3 <BR>\n" );
document.write( "or<BR>\n" );
document.write( "theta = inverseta(12/13) = 122.7<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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