document.write( "Question 170780: At 10:00 AM, a snowstorm is 250 miles west of St. Louis. The storm travels 150 miles eastward at a constant rate, and then its speed decreases by 5 miles per hour. If the storm reaches St. Louis at 8:00 PM, what was the storm's original speed? \n" ); document.write( "
Algebra.Com's Answer #126144 by Mathtut(3670)\"\" \"About 
You can put this solution on YOUR website!
distance equals rate times time
\n" ); document.write( "lets call the 1st 150 miles rate=r and time=t
\n" ); document.write( "and we will call the last 100 miles rate r-5 and time 10-t
\n" ); document.write( ":
\n" ); document.write( "150=rt--->t=150/r.....eq 1
\n" ); document.write( "100=(r-5)(10-t).......eq 2
\n" ); document.write( ":
\n" ); document.write( "take value of t from eq 1 and plug it into eq 2
\n" ); document.write( ":
\n" ); document.write( "100=(r-5)(10-(150/r))--->100=(r-5)((10r-150)/r)...multiply both sides by r
\n" ); document.write( ":
\n" ); document.write( "100r=(r-5)(10r-150)
\n" ); document.write( ":
\n" ); document.write( "\"100r=10r%5E2-150r-50r%2B750\"
\n" ); document.write( "\"10r%5E2-300r%2B750=0\"divide by 10
\n" ); document.write( ":
\n" ); document.write( "\"r%5E2-30r%2B75=0\"\r
\n" ); document.write( "\n" ); document.write( "r=27.25 and 2.75......throw out the 2.75 rate because r-5 is negative.
\n" ); document.write( "so \"highlight%28r=27.25%29\"mph-the original speed of the storm\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B-30x%2B75+=+0\") has the following solutons:
\n" ); document.write( "
\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
\n" ); document.write( "
\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
\n" ); document.write( "
\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-30%29%5E2-4%2A1%2A75=600\".
\n" ); document.write( "
\n" ); document.write( " Discriminant d=600 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--30%2B-sqrt%28+600+%29%29%2F2%5Ca\".
\n" ); document.write( "
\n" ); document.write( " \"x%5B1%5D+=+%28-%28-30%29%2Bsqrt%28+600+%29%29%2F2%5C1+=+27.2474487139159\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-30%29-sqrt%28+600+%29%29%2F2%5C1+=+2.75255128608411\"
\n" ); document.write( "
\n" ); document.write( " Quadratic expression \"1x%5E2%2B-30x%2B75\" can be factored:
\n" ); document.write( " \"1x%5E2%2B-30x%2B75+=+1%28x-27.2474487139159%29%2A%28x-2.75255128608411%29\"
\n" ); document.write( " Again, the answer is: 27.2474487139159, 2.75255128608411.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-30%2Ax%2B75+%29\"

\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );