document.write( "Question 170780: At 10:00 AM, a snowstorm is 250 miles west of St. Louis. The storm travels 150 miles eastward at a constant rate, and then its speed decreases by 5 miles per hour. If the storm reaches St. Louis at 8:00 PM, what was the storm's original speed? \n" ); document.write( "
Algebra.Com's Answer #126144 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! distance equals rate times time \n" ); document.write( "lets call the 1st 150 miles rate=r and time=t \n" ); document.write( "and we will call the last 100 miles rate r-5 and time 10-t \n" ); document.write( ": \n" ); document.write( "150=rt--->t=150/r.....eq 1 \n" ); document.write( "100=(r-5)(10-t).......eq 2 \n" ); document.write( ": \n" ); document.write( "take value of t from eq 1 and plug it into eq 2 \n" ); document.write( ": \n" ); document.write( "100=(r-5)(10-(150/r))--->100=(r-5)((10r-150)/r)...multiply both sides by r \n" ); document.write( ": \n" ); document.write( "100r=(r-5)(10r-150) \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "r=27.25 and 2.75......throw out the 2.75 rate because r-5 is negative. \n" ); document.write( "so \n" ); document.write( "\n" ); document.write( "
\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |