document.write( "Question 170853This question is from textbook
\n" ); document.write( ": Rita rows 12 km upstream and 12 km downstream in 3 hours. The speed of her boat in still water is 9 km/hr. Find the speed of the stream.\r
\n" ); document.write( "\n" ); document.write( "word problem for quadratic equations
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Algebra.Com's Answer #126138 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let s=speed of stream\r
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\n" ); document.write( "\n" ); document.write( "Remember, the distance-rate-time formula is \r
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\n" ); document.write( "\n" ); document.write( "\"d=rt\"\r
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\n" ); document.write( "\n" ); document.write( "\"d%2Fr=t\" Divide both sides by r to solve for t.\r
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\n" ); document.write( "\n" ); document.write( "\"t=d%2Fr\" Rearrange the equation.\r
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\n" ); document.write( "\n" ); document.write( "So when she goes upstream (against the current), the stream is slowing her down. So this means that \"r=9-s\" and \"d=12\". So the equation for the upstream portion of the journey is:\r
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\n" ); document.write( "\n" ); document.write( "\"t=12%2F%289-s%29\" \r
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\n" ); document.write( "\n" ); document.write( "When she goes downstream (with the current), the stream is speeding her up. So this means that \"r=9%2Bs\" and \"d=12\". So the equation for the downstream portion of the journey is:\r
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\n" ); document.write( "\n" ); document.write( "\"t=12%2F%289%2Bs%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now simply add these two equations together to get the total time 3 hours like this:\r
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\n" ); document.write( "\n" ); document.write( "\"12%2F%289-s%29%2B12%2F%289%2Bs%29=3\"\r
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\n" ); document.write( "\n" ); document.write( "\"12%289%2Bs%29%2B12%289-s%29=3%289-s%29%289%2Bs%29\" Multiply both sides by the LCD \"%289-s%29%289%2Bs%29\" to clear the fractions.\r
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\n" ); document.write( "\n" ); document.write( "\"12%289%2Bs%29%2B12%289-s%29=3%2881-s%5E2%29\" FOIL\r
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\n" ); document.write( "\n" ); document.write( "\"108%2B12s%2B108-12s=243-3s%5E2\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"216=243-3s%5E2\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"-27=-3s%5E2\" Subtract 243 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"9=s%5E2\" Divide both sides by \"-3\".\r
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\n" ); document.write( "\n" ); document.write( "\"s=3\" Take the square root of both sides. Note: only the positive square root is considered. \r
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\n" ); document.write( "\n" ); document.write( "So the speed of the stream is 3 km/hr\r
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