document.write( "Question 170841: One common use of positive and negative exponents is in writing numbers as scientific notation. for example 0.000052 can be writtrn as 5.2*10^-5. A) Use scientific notation and the law of exponents to evaluate (0.000054)(0.00000033)(0.013). Leave your answer in scientific notation. B) If a space probe travels at 12 kilometers per second for 10 years, how far will it travel? Write your answer in scientific notation. ( Assume 1 year =365)\r
\n" ); document.write( "\n" ); document.write( "Scientific Notation: A number is expressed in scientific notation when it is in the form a*10^n, where a is greater than or equal to 1 but less than 10 and n is an integer.\r
\n" ); document.write( "\n" ); document.write( "I got the first part, I think.
\n" ); document.write( "5.4*10^-5
\n" ); document.write( "3.3*10^-7
\n" ); document.write( "1.3*10^-2= 23.17*10^-14\r
\n" ); document.write( "\n" ); document.write( "The second part I have no clue.
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Algebra.Com's Answer #126137 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
A) \r
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\n" ); document.write( "\n" ); document.write( "You are doing good. But to get the answer in scientific notation, the first number in front of the \"10 to the exponent\" MUST be in between 0 and 10. So the number 23.17*10^-14 must become 2.3*10^-13 since I shifted the decimal 1 spot to the left.\r
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\n" ); document.write( "\n" ); document.write( "So the answer is 2.3*10^-13\r
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\n" ); document.write( "\n" ); document.write( "B)\r
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\n" ); document.write( "\n" ); document.write( "First, we need to convert 10 years into seconds (we could go the other way, but it might be confusing)\r
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\n" ); document.write( "\n" ); document.write( "Since we're assuming that there are 365 days in a year, multiply 365 by 10 to get\r
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\n" ); document.write( "\n" ); document.write( "365*10=3650 \r
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\n" ); document.write( "\n" ); document.write( "So there are 3,650 days in 10 years\r
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\n" ); document.write( "\n" ); document.write( "Now because there are 24 hours in 1 day, multiply 24 by 3,650 to get\r
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\n" ); document.write( "\n" ); document.write( "24*3,650 = 87,600\r
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\n" ); document.write( "\n" ); document.write( "So there are 87,600 hours in 10 years.\r
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\n" ); document.write( "\n" ); document.write( "Since there are 60 minutes in an hour and 60 seconds in a minute, there are 60*60=3600 seconds in an hour\r
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\n" ); document.write( "\n" ); document.write( "Now simply multiply 3,600 by 87,600 to get\r
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\n" ); document.write( "\n" ); document.write( "3,600*87,600 = 315,360,000\r
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\n" ); document.write( "\n" ); document.write( "So there are 315,360,000 seconds in a year\r
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\n" ); document.write( "\n" ); document.write( "Since \"t=10\" years, this means that \"t=315360000\" seconds which in scientific notation is \"t=3.15%2A10%5E8\"\r
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\n" ); document.write( "\n" ); document.write( "\"d=rt\" Start with the distance rate time formula\r
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\n" ); document.write( "\n" ); document.write( "\"d=12%283.15%2A10%5E8%29\" Plug in \"r=12\" and \"t=3.15%2A10%5E8\"\r
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\n" ); document.write( "\n" ); document.write( "\"d=37.8%2A10%5E8\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"d=3.78%2A10%5E9\" Shift the decimal one spot to the left (this will raise the exponent by 1)\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"d=3.78%2A10%5E9\" km which is 3,780,000,000 km. In words, this distance is 3 billion, 780 million kilometers.
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