document.write( "Question 170799: At 7:00 a.m., Joe starts jogging at 6 mph. At 7:10 a.m., Ken starts off after him. How fast must Ken run in order to overtake him at 7:30 a.m.? \n" ); document.write( "
Algebra.Com's Answer #126119 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! At 7:00 a.m., Joe starts jogging at 6 mph. At 7:10 a.m., Ken starts off after him. How fast must Ken run in order to overtake him at 7:30 a.m.? \n" ); document.write( ": \n" ); document.write( "From the information given we can say: \n" ); document.write( "Joe's travel time = \n" ); document.write( "Ken's travel time = \n" ); document.write( ": \n" ); document.write( "Let s = Ken's jogging speed \n" ); document.write( ": \n" ); document.write( "When Ken overtakes Joe, they will have traveled the same distance \n" ); document.write( "Write a distance equation from this fact; Dist = Time * speed \n" ); document.write( ": \n" ); document.write( "Kens dist = Joe's dist \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply both sides by 6 to get rid of the denominators \n" ); document.write( "2s = 3*6 \n" ); document.write( "2s = 18 \n" ); document.write( "s = 9 mph is Ken's speed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution by finding the dist: \n" ); document.write( " \n" ); document.write( " |