document.write( "Question 170747: I need some help with this problem.
\n" ); document.write( "i asked my friend to help me with a previous problem and he ended up just giving me the answer cause i still don't get it.
\n" ); document.write( "The one already answered ==
\n" ); document.write( "\"\":How i tried to work it out.
\n" ); document.write( "[]:my answer\r
\n" ); document.write( "\n" ); document.write( "1. \"+2x%5E2-10x%2B12=0+\"
\n" ); document.write( "\"2(x+6)(x-1)\"
\n" ); document.write( "[x=6,(-1)]
\n" ); document.write( "Was that correct?\r
\n" ); document.write( "\n" ); document.write( "2. \"+x%5E2%2B2x=-11+\"
\n" ); document.write( "?????\r
\n" ); document.write( "\n" ); document.write( "Please help me.
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Algebra.Com's Answer #126061 by Mathtut(3670)\"\" \"About 
You can put this solution on YOUR website!
It is not real clear what you are asking but I have a feeling you were given a solution set of x =6 and -1 and were asked to form a quadratic equation from this solution set...So we must work backward remember a quadratic equation takes the form of \"Ax%5E2%2BBx%2BC=0\" and when factored each factor is set to zero and the solution is found. In this case we are working backward
\n" ); document.write( "so....x=6...in order to make x term = to zero we must subtract 6 so x-6=0....now for x=-1 we must add 1......and get x+1=0 now these two terms can be multiplied together and set equal to zero
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\n" ); document.write( "(x-6)(x+1)=0--->now multiply this out using foil
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\n" ); document.write( "\"x%5E2%2Bx-6x-6=0\" combine like terms
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\n" ); document.write( "\"x%5E2-5x-6=0\" is our quadratic equation\r
\n" ); document.write( "\n" ); document.write( "If this doesnt answer your question you will have to re write your question and make it more clear....
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