document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=170715>Question 170715</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a solution contains 4% salt. how much pure water should be added to 30 oz of the solution to dilute it to a 1.5% salt solution?\r<BR>\n" );
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document.write( "thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #126026 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=126026\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> so the portion of salt in the solution is .04(30)=1.2 oz----> this portion of salt does not change it simply becomes more diluted if pure water is added. The 1.2 ounces must be equal to 1.5% of what ever the new mix is....we know we already have 30 oz so whatever is added(water in this problem-which we will call x) has to be combined with the existing 30 oz as is stated in the problem.....so we end up with the new mix equaling 30+x\r<BR>\n" );
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document.write( "1.2=.015(30+x)<BR>\n" );
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document.write( "1.2=.45+.015x<BR>\n" );
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document.write( ".75=.015x<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28x=50%29 ALIGN=MIDDLE  ALT=\"highlight%28x=50%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >oz of pure water need to be added </SPAN>\n" );
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