document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=170692>Question 170692</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A sailboat travels 20 miles downstream in 3 hours. It returns in 4 hours. Find the speed of the sailboat in still water and the rate of the current.\r<BR>\n" );
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document.write( "Help, no idea.\r<BR>\n" );
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document.write( "Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #126019 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=126019\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A sailboat travels 20 miles downstream in 3 hours. It returns in 4 hours. Find the speed of the sailboat in still water and the rate of the current. <BR>\n" );
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document.write( "Downstream DATA:<BR>\n" );
document.write( "distance = 20 miles; time = 3 hrs. ;rate = d/t = 20/3 mph<BR>\n" );
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document.write( "Upstream DATA:<BR>\n" );
document.write( "distance = 20 miles; time = 4 hrs. ;rate = d/t = 20/4 = 5 mph<BR>\n" );
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document.write( "Let still water speed be \"b\"; Let current speed be \"c\"<BR>\n" );
document.write( "Downstream: b + c = 20/3 mph<BR>\n" );
document.write( "Upstream  : b - c = 5<BR>\n" );
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document.write( "2b = 35/3<BR>\n" );
document.write( "b = 35/6 = 5 4/6 mph (boat speed in still water)<BR>\n" );
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document.write( "Use b -c = 5 to solve for \"c\".<BR>\n" );
document.write( "35/6 - c = 30/6<BR>\n" );
document.write( "c = 5/6 mph (current speed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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