document.write( "Question 170691: When the digits of a two-digit number are reversed, the new number is 9 more than the original number, and the sum of the digits of the original number is 11. What is the original number?\r
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Algebra.Com's Answer #126010 by Mathtut(3670) $\"\"$ $\"About$

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lets call the 10 digit number a and the ones digit number b.
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\n" ); document.write( "remember a two digit number take 35 for instance can be written as 3(10)+5(1)
\n" ); document.write( "with that in mind lets write and equation based on that understanding.
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\n" ); document.write( "10(a)+1(b)=(10(b)+1(a))+9--->9a-9b=9--->a-b=1....eq 1
\n" ); document.write( "a+b=11.................................eq 2
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\n" ); document.write( "add the 2 equations together to eliminate the b term.
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\n" ); document.write( "2a=12
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\n" ); document.write( " $\"highlight%28a=6%29\"$
\n" ); document.write( " $\"highlight%28b=11-%286%29=5%29\"$ \n" ); document.write( "

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