document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=23863>Question 23863</A>: <I><SPAN STYLE=\"word-break: break-all;\">  <BR>\n" );
document.write( " ive tried to do this and i am stuck!!\r<BR>\n" );
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document.write( "  \" The second of two numbers is 3 less than twice the first. Their sum is 42. Find the numbers.\"\r<BR>\n" );
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document.write( "x = first number = <BR>\n" );
document.write( "4x - 2 = second number = </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #12596 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=12596\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First number = x<BR>\n" );
document.write( "Second number = 2x-3<BR>\n" );
document.write( "Sum = 42\r<BR>\n" );
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document.write( "(x)+(2x-3)=42<BR>\n" );
document.write( "3x-3+3=42+3<BR>\n" );
document.write( "3x=45<BR>\n" );
document.write( "x = 15 (first number)\r<BR>\n" );
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document.write( "2(15)-3=27(second number)\r<BR>\n" );
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document.write( "Hence, the two numbers are 15, and 27<BR>\n" );
document.write( "Paul.  </SPAN>\n" );
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