document.write( "Question 170632This question is from textbook Algebra structure and method book one
\n" ); document.write( ": Find the dimensions of a rectangle whose perimeter is 46m and whose area is 126m^2. \n" ); document.write( "
Algebra.Com's Answer #125959 by checkley77(12844)\"\" \"About 
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P=2L+2W
\n" ); document.write( "A=L*W
\n" ); document.write( "46=2L+2W
\n" ); document.write( "126=L*W OR L=126/W
\n" ); document.write( "46=2(126/W)+2W
\n" ); document.write( "46=252/W+2W
\n" ); document.write( "46=(252+2W*W)/W
\n" ); document.write( "46=(252+2W^2)/W
\n" ); document.write( "46W=252+2W^2
\n" ); document.write( "2W^2-46W+252=0
\n" ); document.write( "2(W^2-23W+126)=0
\n" ); document.write( "2(W-14)(W-9)=0
\n" ); document.write( "W-14=0
\n" ); document.write( "W=14 & L=9
\n" ); document.write( "W-9=0
\n" ); document.write( "W=9 & L=14
\n" ); document.write( "PROOF:
\n" ); document.write( "46=2*14+2*9
\n" ); document.write( "46=28+18
\n" ); document.write( "46=46
\n" ); document.write( "14*9=126
\n" ); document.write( "126=126\r
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