document.write( "Question 170632This question is from textbook Algebra structure and method book one
\n" );
document.write( ": Find the dimensions of a rectangle whose perimeter is 46m and whose area is 126m^2. \n" );
document.write( "
Algebra.Com's Answer #125959 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! P=2L+2W \n" ); document.write( "A=L*W \n" ); document.write( "46=2L+2W \n" ); document.write( "126=L*W OR L=126/W \n" ); document.write( "46=2(126/W)+2W \n" ); document.write( "46=252/W+2W \n" ); document.write( "46=(252+2W*W)/W \n" ); document.write( "46=(252+2W^2)/W \n" ); document.write( "46W=252+2W^2 \n" ); document.write( "2W^2-46W+252=0 \n" ); document.write( "2(W^2-23W+126)=0 \n" ); document.write( "2(W-14)(W-9)=0 \n" ); document.write( "W-14=0 \n" ); document.write( "W=14 & L=9 \n" ); document.write( "W-9=0 \n" ); document.write( "W=9 & L=14 \n" ); document.write( "PROOF: \n" ); document.write( "46=2*14+2*9 \n" ); document.write( "46=28+18 \n" ); document.write( "46=46 \n" ); document.write( "14*9=126 \n" ); document.write( "126=126\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |